2x^2+11x+12=180

Solution for 2x^2+11x+12=180 equation:

2x^2+11x+12=180

We move all terms to the left:

2x^2+11x+12-(180)=0

We add all the numbers together, and all the variables

2x^2+11x-168=0

a = 2; b = 11; c = -168;
Δ = b2-4ac
Δ = 112-4·2·(-168)
Δ = 1465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1465}}{2*2}=\frac{-11-\sqrt{1465}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1465}}{2*2}=\frac{-11+\sqrt{1465}}{4}
$